Quantitative equilibrium calculations

Fundamentals
Problems
Excercises for improved understanding
     5 ml water instead of 1 ml
     2 ml air volume instead of 1 ml
     25 ml air volume instead of 5 ml
     Volumes are doubled
     Total amount of the substance is doubled
     Initial situation changes
Questions for recapitulation
Good to know
Minesweeper-problems

Excercises for an improved intuitive understanding

After working through these problems you should have developed a good overview of how partition constants can be applied to solve quantitative partition problems. But do you also have a good ´intuitive´ understanding of how partition systems respond to changes of one or several variables? If you change the volume of a phase or a partition constant then some of the system responses (like changes in equilibrium concentrations, mass fractions) are proportional to the changed variable while others are not. An example for a non-linear response is the fact that you will need 10 times more solvent to extract 99% of a chemical out of a water sample than if you wanted to extract only 90% (see problem Organic pollutants in water). The following exercise is intended to train your intuitive understanding of partition processes (corresponds to Box 3 in the script).

 

Exercise for a better understanding of the system response of a simple partition system:

Use sheet 1 of the Mehr-Phasensystem.xls to calculate the equilibrium state of 1 ng of a compound i in the following partition system: 1 ml air, 1 ml water and a Ki aw of 0.1 [Lwater / Lair ]. Try to estimate (not calculate yet) how the concentrations of i and the mass fraction of i in both phases change if you change the system as follows:

5 ml water instead of 1 ml

2 ml air volume instead of 1 ml

25 ml air volume instead of 5 ml

What will happen if both volumes are doubled?

What will happen if the total amount of the substance is doubled?

What will happen if the Henry constant is reduced by factor 10 in comparison to the initial situation?