Equilibrium partitioning of organic compounds

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     Sorption isotherm
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Sorption isotherm

Answer:The experiment will result in a linear relationship (i.e., constant slope of the curve) with zero as the ordinate intercept (Note that zero concentration in phase 1 must correspond to zero concentration in phase 2).

The partition constant is identical to the slope of this curve because K equals c*i 1 /c*i 2 .

If i was a volatile compound and the bottle also contained 1 L of air while the same amounts of i were added to the system like before, then the measured concentrations in phase 1 and 2 would be smaller than in the absence of air in the system. However, the data points would still lie on the same straight line as the one shown above.

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